How to find a1?



If you want to find the nth element in a series, you have to solve for the nth term. In this problem, the nth term is the first term of the sequence. To solve it, you can use the formula given below. You can then substitute both a1 and d to get the solution. The formula for a12 is the twelfth term of the arithmetic progression.

Another example is to solve for the difference between two numbers. The second term of an arithmetic progression is equal to a1 – nk, where a1 = nk. The first term is a 1, while a2=2b. So you can see how to find a1 with a similar formula. The first term of a series is a1, and the second one is a2.

The second term in the arithmetic sequence is a2. The nth term is the a1 – d. In this example, a1 + d=27, and a2 = 60. Likewise, d=a1 – d. In the second example, the nth term is a1, and the nth term is d. So if n = 1, then a1-d is a2. Similarly, a8 is sixty, and the nth term is a1. So, d=a1 – n2.

How to Find the Nth Element in a Series

If the arithmetic sequence has a first term a 1, the nth term is a1. If a8 has a first term a 1 – d, the 27th term is a1. The first term of a series is a2, d=a1 – nk. So, a1+nk=b2, d. This is the nth term. The nth term is a2, d=b.

In arithmetic progression, the first term is a1. The nth term is a1. The first term has a common difference d. In the first example, a1+n =27. d. The nth-term of a series has a fifth. Therefore, the nth term of a series is the same as a1+n. So, d is a2.

an=a1+(n-1)d

The formula a1+dn is the first term of an arithmetic progression. The second term is the nth term of the arithmetic progression. Moreover, this formula is called arithmetic progression. The nth-term of a sequence is equal to the first term a+dn minus dn. The nth-term of n is the same as a1+dn.

2,6,10,14 sequence

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